Estudo de Anfolitos Redox

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Anfolitos redoxAnfolitos redox
Aniolitos estables e Ines tables
Nz NO}
-
11105 NO
I 1 +
-
I Eo(ENµ ,
Anfolitosestabilidad dual secombortan Como oxidants yreductores
- 0.214/0.7/89 0.96 1.68
MLAs
É 1402 NO Nz
A-nfolito Esta ble : Nz
+
( NZHS + I 1112 + 511+-1 4e - 1414=1 (4)(4)
a
11.68 - C- 0.21411
He
-
+ 41-1++2140 1h12 + 21-1201414=7 log K =
g.gg
= 126.27 → 11--70116.27
Melts
+
+ 2h10 + 12h12 + It -1+21-120 Reaction deformation
H -1+2142 + 21110 1111211-5++21110-1 Reunion de dismutacio
Anfolitolnestable : NO instable Dorquereuccionaconsiyomismo Dismotuciinporque et NO se dis Muta
( 211-20 + NO → 1405 + 41T + + 3. e- 14
4
14 e- + 4h -1 + 2h10 → Nz + 21-12013 loykdism = (4) (3) (1.68-0.96) = 144 → kdism = 10744
211-20+101110 → 411105+31112+41-1 -1 Reunion de dismutacioñ del NO 0.06
DUZD Diagram unidimensional de tonus depredominio .
Oxidants tienen Valores de predominiomuyoresal 0i= Qox ,= Ichi ]
"" d
"
f. 0 (f. NH) potenciulestandur.
" Ioxdi ]+TRedi]
[ red , ,
[ µEj Los reductores tienen Valores depedominiomenoreis red , , Fredi]
Ioxai tired ;]at potential estundur
.
[Redi]
F- = EY + 0.0¥ log¥7
FrediRed
,
0"
geo ,Eµµ ,
Oi -- Fraccijndeespecieo Abundunciu
¥
i. iloxd ; , Red ;)
Ret """" ¥7
= 10 mcfÉf÷
Fredi
1 . ①Oxdi
+ ① red i = I
^
Oloxd , = É%÷} ① redi = 1-
oxdi = 1- Oredi
Oi - Fest Eoxdi] É¥÷? + I+ I
- Feet [ Redi ]0.5-I ni LE - ETI
Ooxi = 10 0.06
nitti - Egg
① redi = 1
gon ' "=_o +101.77 E 10 -0.06 +1
Fe
"
Fey
,
!; , lv " lot/ I 1 y Et lo " , lo" (v0 , loj Loo (v2 ' ,
- 0.44 I
0.153 0.521 0.153 0-521 Eodism
lot 100
Cut 1 (v2
'
+ e-
e- + (ut ) Luo
"" +
Nafi + nzEz°µÉ+ 1 IE ' Eodism =210-1 Itv2 -1 + (v0 Eodism hi + nz- Fest
I Eodism = 17110.5211+4110.1531 = 0.337
- 0.44 0.77
I + 1
Fe Fe
" Fest
11-11=-0 ^
-0.44 0.77
- (v0Oi
- Co2 -1
- luteiquesedismuta
"
F-
Una disunion con cations hipoteticos
Amica Que
' Dotencial Dura tener
593-1 IT = 0.1 MOI
I IEO F-
= ? I
M+ 173-1 : Mt ( 70 : 30 )
0.96
✗
7
I
0.3 = Me = zce-o.gg ,
0 E-- 0.96 + 0¥ log É¥?¥-
10 -0.06 + I Y 3
E = 0.971
Determine lusconcentraciones
593-1
1 YEO
IM } 'T = ? E = 0.911
Mt In -1 ] = ?
0.96
,
0.9=0.96 + 00¥ log IM [573-1] + [17-1]=0.2(i = 0.2M¢
[1-9-1]
① it -1 =
1
[1--1-1]=0.9907 ✗ 0.2 = 0.198 M¥
2 (0.9-0.96) = 0.9907
10 0.06 + 7 [ 1-93+7=0.0099×0.2 = 0.0078m¥
M3 -1 = 1 - ① 1--1-1 = 0.0099
reauionesdeanfolizuciinydismotaa.in .
Fe 2
+
(v2-1 (ut Fe 3 -1
' l l 1 EYE ,yµ ,
Antolitos es tables Fez -1
- 0.44 0.153 0.521 0.77 Anfolitog ine stables lot
Feo cut ( v0 Felt
Reunion de anfoliiaciin Reunion dismotuciin
(Feo 1 Feat + Ze - ) I 1 lot 1102 + + e- 17
( e - + Fe 3+-7 Fez -112 ( e- + lot -1 (v0) 2
Feo + 2 Fest → 3Fe 2 + 210-1 → (v3 -1 + (v0
log K
"to! 12111110.77 - l - 0.991
= go.gg log
Kdism= (1) (1) (0.527-0.153)
= 6.13
0.06 0.06
Kanto / = 1040-33 kdigm= 106-13
Reunion de dismutacicin Feat reunion deanrolizuciondel lot
3. Felt -1 Feo -1 Lte >
+
103-1 + 100 -12 Cut
kdism = go -40.33 Kanto/ = 70-6-13
Deduction elocution E = MET + nzf.io
My + Nz
condition :(antidudestequiometricas deoxdi y Rede
Oxdz Oxdi
E = EY + 0¥ log told]
I 1 / F. 0 IENH ) [ Redi]
ME + ME = MET + 0.0610g -10×41-7 + ME20+0.06 log [0×-42]
F-2° E'°
ME = n, Io, + o.gg/ogI0Xd1T-
[Redl] [ Redl ]
Redl Redl [ Redi ] 70
F. ( ni th2) = MET + nz Ei +0.0610g Foxd 7) [0×42]
ni F- = MIEY + 0.0610g
10¥ [ Redi]IRedz](Oxdi + nie - → Red 1) nz
[ red , ] toga + log
b = 1094h
( Redz I Oxdz + me- Ini n2E = MET +0.0610g [0×4-2]
[ Red 2 ]
: . f. =
MET + NIET
nz Oxdi + Red 2ns→ Red m2 + OXDZM
ni + nz
Tarea 5Tarea 5 En Toda reaction DonerescaladeDotenciul
5- 2
, ,
"
if; Fest ( eat
Ba2ta+G#
- 2.92 -1.68 -0.65 -0.95 -0.26 0.14 0.62 1.19
Bao Ato Ga " Gao y 2- 10
-
l
-
Iz felt 63't
- h
o
Anfolitoestable :
Ii Dor pendienteneydtivu
Anfolitoi nestable :
Gu
" pendiente positive reaccionuconsigomismu
Valor del logaritmo de la Constante de anr-olizuu.in para el Galt :
( ie - + Ga " Ga" )z logkan.ro/ = (2) (1) (-0.65-1-0.45)=-6.667
( Guo ) Galt + Ze
-
17 0.06
2ha 's -1 + Gao 3Ga2
-1
Valor del logarithm de la Constante de dismutaliinpuruelkes : now,
( Ie - + 12 21-1192=5 , Iogkdism = 2=(0-62--1.19) = -95
( 6h20 + 12 12103
-
+121-1++10e- 12/2=1
0-06
611-20 +612 1 101-+2103-+121-1 "
F. I Ga " dismuta a Ga} " y Gametalilo Clout eselxulor de Ioaism ?
( Ga
" Gu" + ie - 12 Eod;gm=
MET + nzEz°
= (-0.65×11+1211-0.45)=-0.51667
MY 1- Nz
2 +1
( Ze - + Ga" ) Gao 11
Ze
-
+ 3ha 2-1 12kg3 -1 + Guo
Se disoelven 0.3543g de 11103 en oicidoclorhidrico 1m01 / L hasta obtener 500mL de dis ( F-0110511-101=1.1911 , Io Hsl 061105 /
=
1.6 11 19191403 214.001g /Mol
logaritmo de la ite deformation del 105 a fueriaionilanulaes: ktermodinumicu
,
103
- 11-5106 MM Klos 214 Imo,
121.120+11-10 1 105+511--1+451212=1 12¥41 (1.60-1.14)
He- + 1-1++14,106 105+31-1201412--2 109k = = 30.6667
0.06 1.144 1.6 L
1-110+211-5106 3103-+31-1++91120 I10 1--05
Loguritmodelaionstante deformation del 10; a tu Fuerza ioniiudeludisoluciories:
0.3543g 11103 . 1m01 1<103 . o.gl , = 3.31119948×70-3101-1403214.007g KIO]
21-120+1-110 -
' 105 + 5H+ K = I
1-It +1-15106 ,
' 105+31-120
logy ,,; -
0.512 /till I
= -
0.5121-1123.312×10-3
' + I I +
, 3.312×10-3
= -0.027858 Kam : k÷,y
,
.
=
30.6667
( 10-0.027-85046
=
45.063
/ Ogyp, ,
=
-
0.51212-112 I
= -
0.5121-1123.312×10-3
' + ± I +
, 3.312×10-3
= -0.027858
Si solo se consideran Ios valores de potentiates normales para el Sistema de vrunio : F.
° V0 ? " / V02 -1=0.0511 y F- 0002+1002-1=0.6211
1002++1-120 1 ie
-
+ 21-1++002+11 [odigm =
MET + nzEÉ
UOÉ V02 +
( ie - ← Voit y v02-111
97-1^2
0.05 0.62 Eodism = 0.05+0.62 = 0.335
voi v02
"
logk = 11111110.05 -0.62 ) = - qg 2
0.06
Con una disolucijn de 2 ioneshinoteticos de M " ✗ N'
+
con concentration 0.1 moth Seimnone un potential -0.711 queconcentration
yueda de Ms
'
yn " en MOI / L
143-1 593-1
f-Mie ]
-
-0.763 -0.44 IN
] -1 ]
N -1 Mt
IT :O . / MOHL 0.7=-0.44+0.66 log
I ]
[1-91-1]
( Mst ) + Itglt ] = g.,
2 1-91-1 = 0.7 - 1-93-1
( 0.7 +0.4412
0.06 = log } 1 = 1038 = +
10 70 ( Mit ) 1038 = 1×13-1
( 0 . I - 1-93+1 1038=173-1
0.1 × 1038 = 173+-2848.035868 ← 1-93-1
0.1 × 1038
= 1-93 -1=0.1
①oxdi + ① red i = I 10" +1
Mit = 0.9
① oxdl = I - Oredi
210.7+0.44)
10 0.06
① i't '
'
= = I 7 ITT 's
-1 ] = 10513 -1 . G- =L I 110.11=0.1
210.7 -10.441
10 0.06 + I
01×3-1 = 7021
631
102 ,
= I \ IN 't ] = ①N'
+
. It = (1) ( 0.1 ) = 0.1
se reduce el 100% ?
1--13-1 ) Mt
0.1
± 10.03
0.07
La reunion de dismutuciineslurder-ormaciindelantoli.to
Fatso
Lu reunion de anioliiacicineslureuuiin deformation de un anfolito
Yeodudero
si I = 0 : . log 8 = 0
Ko = Kann