E 107- Draw the curve y = 4/(16 + 2ax - ay)^(2/3) + (64ax)/(16 + 2ax - ay)^(2/3), for a = 1 and a = -1.

The curve is symmetric with respect to the XX' axis.
For a = 0 and a = k, the curve is reduced to the XX' axis.
The curve has a parabolic branch along the XX' axis.
The curve has a turning point at the origin with a tangent line y = 0.
The curve intersects the XX' axis at (0,0) and the YY' axis at (0,±4^(2a)/2).
For a > 0, the curve is real for x ≤ 3a/4, being the line x = 3a/4 tangent at (3a/4,±2a).
For a < 0, the curve is real for x ≥ -3a/4, being the line x = -3a/4 tangent at (-3a/4,±2a).
a) All afirmacoes are correct.
b) Only afirmacoes 1, 2, 3, and 4 are correct.
c) Only afirmacoes 1, 2, 5, and 7 are correct.
d) Only afirmacoes 2, 3, 4, and 5 are correct.