E 108- Study the curve (x^2 - 4)^2 + (y^2 - 1)^2 = a^4, as a varies from 0 to k.

The curve is symmetric with respect to the X and Y axes and the origin.
The curve intersects the X and Y axes at (±4^(a^2) - 1,0) and (0,±1^(a^2) - 4).
For a^2 = 0, the curve reduces to four points, one in each quadrant.
For 0 < a^2 < 1, the curve is formed by four ovals, one in each quadrant, that do not intersect the axes.
For a^2 = 1, the ovals in the 1st and 4th quadrants, and those in the 2nd and 3rd, have a common point on the XX' axis, whose coordinates are (±2,0).
For 1 < a^2 < 4, the curve consists of two ovals, one in the 1st and 4th quadrants, and another in the other two quadrants.
For a^2 = 4, the two ovals of the previous case have two common points located on the YY' axis.
a) All afirmacoes are correct.
b) Only afirmacoes 1, 2, 3, and 4 are correct.
c) Only afirmacoes 1, 2, 5, and 7 are correct.
d) Only afirmacoes 2, 3, 4, and 5 are correct.