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Física: Curso de nivelación Julián Eduardo Corrales Hernández DNI: 43.418.041 Legajo: 805333 Trabajo Practico: Magnitudes y Unidades. 1- a- 1mi x (5280ft/1mi) (12in/ 1ft) (2.54cm/1in) (1m/100cm) (1km/1000m) = 1.61km b- 1km x (1000m/1km) (100cm/1m) (1in/2.4cm) (1ft/12in) = 3280ft 2- Frasco = 0.473L 0.473L (1000cm3/1L) (1in/2.54cm) (1in/2.54cm) (1in/2.54cm) = 28.9in3 3- 11.3g/cm3 (1Kg/1000g) (100cm/1m) (100cm/1m) (100cm/1m) = 11300 Kg/m3 4- a) (1mm/7mm) x 100 = 0.13% b) (0.01g/12g) x 100 = 8.3x10-3% c) (1cs/3600cs) x 100 = 2.8x10-2 5- Ancho = 5.10 -Max: 5.10 + 0.01 = 5.11 -Min: 5.10 – 0.01 = 5.09 Alto = 1.9 -Max: 1.9 + 0.01 = 1.91 -Min: 1.9 – 0.01 = 1.89 Respuesta: A=9.69 0.07cm2 6- a) 0.850 0.285cm3 b) 8.5cm/0.0150cm 189.5cm3 Trabajo Practico: Vectores 1- a) A + B = C C = (2.35, 0.78) Magnitud = 2.48cm Direccion = 18.4° b) A – B = C C = (0.45, 4.07) Magnitud = 4.09cm Direccion = 83.7° 2- Vector equilibrante de A = (-1.4, -2.4) Vector equilibrante de B = (-2.4, 1.64) 3- A = (1.23i + 3.38j) N = (-20.7i - 12j) C = (21.93i + 15.38j) 4- A = x = 100 x cos 30° = 86.60 y = 100 x sen 30° = 50 Li = x = 80 x -sen 30° = -40 y = 80 x cos 30° = 69.28 E = x = 40 x -cos 53° = -24,07 y = 40 x -sen 53° = -31.94 R= = 90.20N = arctan (87.35/22.53) = 75.54° 5- C = A + B // C – B = A A = x = 3.03 Magnitud de A = 5.20cm y = -3.31 Dirección = -2.48° B = x = 6.40 x cos 63° = 2.91 y = 6.40 x sen 63° = 5.70 C = x = 6.40 x cos 112° = -2.40 y = 6.40 x sen 112° = 5.93 6- B + C = D // C = D - B A = 2km B = 3.5km C = X D = 3.8km Respuesta: -Magnitud 2.8km -Dirección: 61.70° Trabajo Practico: Cinemática Unidimensional 1- a) = (1000 – 63) / (5.9 – 1.15) = 197.26m/s b) = (1000 – 0) / (5.9 – 0) = 169.49m/s 2- a) Se van a encontrar a los 54.05s b) Cuando hayan recorrido: Corredor1: 355.11m Corredor2: 135.12m c) 22.98s Corredor1: 142.47m Corredor2: 57.45m 3- a) b) -(0s, 2s): (6ms-0ms) / (2s-0s) = 3m/s2 -(2s, 4s): (10ms-6ms) / (4s-2s) = 2m/s2 -(4s, 6s): (16ms-10ms) / (6s-4s) = 3m/s2 -(6s, 8s): (18ms-16ms) / (8s-6s) = 1m/s2 -(8s, 10s): (20ms-18ms) / (10s-8s) = 1m/s2 -(10s, 12s): (22ms-20ms) / (12s-10s) = 1m/s2 -(12s, 14s): (22ms-22ms) / (14s-12s) = 0m/s2 c) La aceleración es constante en el intervalo (6s, 12s). Y no es acelerada en el intervalo (12s, 14s). 4- a) 11m = a . (4s)2 = a = 1.375m/s b) No hay aceleración. c) Vf = Vo + a . t Vf = 1.375 . 4 = 5.5m/s 5- a) 8s: (44.72m/s – 0m/s) / (8s – 0s) = 5.59m/s2 60s: (447.22m/s – 0m/s) / (60s – 0s) = 7.45m/s2 8s, 60s: (447.22m/s – 44.72m/s) / (60s – 8s) = 7.74m/s2 b) (0s, 8s): 357.76m (8s, 60s): 26.83km 6- 0s: 0m, 0m/s2, 0m/s 2s: 9m, 1m/s2, 4m/s 4s: 16m, 2m/s2, 8m/s 6s: 40m, 0.75m/s2, 8m/s 7- a) Vf = 48.59m/s b) T = (120m)/ (48.59m/s) = 2.46s c) Vf = -44.59m/s 8- b- no se chocan 9- a) Persona caminando: x = x0 + v . t x = 0 + 0.67m/s . 0.538s x = 0.360m Huevo: 1.75m = 3.2m + 0m/s . t – 1/2 (9.8m/s) . t2 T= 0.538s b) 1.75m = 3.2m + 0.67m/s . t – 1/2 (9.8m/s) . t2 T= 0.616s X = 0 + 0.67m/s . 0.616s X = 0.412m
Cristian Henrry QN
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